Base | Representation |
---|---|
bin | 10010101001100011… |
… | …00011101110100011 |
3 | 221211202202002000112 |
4 | 21110301203232203 |
5 | 131001111242011 |
6 | 4333300241535 |
7 | 503053253555 |
oct | 112461435643 |
9 | 27752662015 |
10 | 10012212131 |
11 | 42786a6189 |
12 | 1b350a02ab |
13 | c373a4b9c |
14 | 6ada214d5 |
15 | 3d8ec158b |
hex | 254c63ba3 |
10012212131 has 2 divisors, whose sum is σ = 10012212132. Its totient is φ = 10012212130.
The previous prime is 10012212103. The next prime is 10012212151. The reversal of 10012212131 is 13121221001.
10012212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10012212131 - 210 = 10012211107 is a prime.
It is a super-2 number, since 2×100122121312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10012212151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006106065 + 5006106066.
It is an arithmetic number, because the mean of its divisors is an integer number (5006106066).
Almost surely, 210012212131 is an apocalyptic number.
10012212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012212131 is an equidigital number, since it uses as much as digits as its factorization.
10012212131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 10012212131 its reverse (13121221001), we get a palindrome (23133433132).
The spelling of 10012212131 in words is "ten billion, twelve million, two hundred twelve thousand, one hundred thirty-one".
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