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10012212131 is a prime number
BaseRepresentation
bin10010101001100011…
…00011101110100011
3221211202202002000112
421110301203232203
5131001111242011
64333300241535
7503053253555
oct112461435643
927752662015
1010012212131
1142786a6189
121b350a02ab
13c373a4b9c
146ada214d5
153d8ec158b
hex254c63ba3

10012212131 has 2 divisors, whose sum is σ = 10012212132. Its totient is φ = 10012212130.

The previous prime is 10012212103. The next prime is 10012212151. The reversal of 10012212131 is 13121221001.

10012212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10012212131 - 210 = 10012211107 is a prime.

It is a super-2 number, since 2×100122121312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (10012212151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006106065 + 5006106066.

It is an arithmetic number, because the mean of its divisors is an integer number (5006106066).

Almost surely, 210012212131 is an apocalyptic number.

10012212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012212131 is an equidigital number, since it uses as much as digits as its factorization.

10012212131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10012212131 its reverse (13121221001), we get a palindrome (23133433132).

The spelling of 10012212131 in words is "ten billion, twelve million, two hundred twelve thousand, one hundred thirty-one".