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10012231320131 is a prime number
BaseRepresentation
bin1001000110110010011101…
…1111011100001001000011
31022110011022121121200202002
42101230213133130021003
52303020022204221011
633143320000414215
72052234266012615
oct221544737341103
938404277550662
1010012231320131
11321018861a957
12115853001736b
135781c31c2161
14268847762db5
15125693b57c3b
hex91b277dc243

10012231320131 has 2 divisors, whose sum is σ = 10012231320132. Its totient is φ = 10012231320130.

The previous prime is 10012231320073. The next prime is 10012231320199. The reversal of 10012231320131 is 13102313221001.

It is a happy number.

10012231320131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10012231320131 - 210 = 10012231319107 is a prime.

It is a super-2 number, since 2×100122313201312 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (10012231320031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006115660065 + 5006115660066.

It is an arithmetic number, because the mean of its divisors is an integer number (5006115660066).

Almost surely, 210012231320131 is an apocalyptic number.

10012231320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10012231320131 is an equidigital number, since it uses as much as digits as its factorization.

10012231320131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 10012231320131 its reverse (13102313221001), we get a palindrome (23114544541132).

The spelling of 10012231320131 in words is "ten trillion, twelve billion, two hundred thirty-one million, three hundred twenty thousand, one hundred thirty-one".