100123000203113 has 4 divisors (see below), whose sum is σ = 100626130857600. Its totient is φ = 99619869548628.

The previous prime is 100123000203101. The next prime is 100123000203139. The reversal of 100123000203113 is 311302000321001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100123000203113 - 2¹⁰ = 100123000202089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100123000203091 and 100123000203100.

It is not an unprimeable number, because it can be changed into a prime (100123000203613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251565326945 + ... + 251565327342.

It is an arithmetic number, because the mean of its divisors is an integer number (25156532714400).

Almost surely, 2^{100123000203113} is an apocalyptic number.

It is an amenable number.

100123000203113 is a deficient number, since it is larger than the sum of its proper divisors (503130654487).

100123000203113 is an equidigital number, since it uses as much as digits as its factorization.

100123000203113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 503130654486.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 100123000203113 its reverse (311302000321001), we get a palindrome (411425000524114).

The spelling of 100123000203113 in words is "one hundred trillion, one hundred twenty-three billion, two hundred three thousand, one hundred thirteen".