Base | Representation |
---|---|
bin | 1001000110110010110011… |
… | …1101111100000010110011 |
3 | 1022110011120000111201212202 |
4 | 2101230230331330002303 |
5 | 2303020214214414303 |
6 | 33143333042013415 |
7 | 2052236463001511 |
oct | 221545475740263 |
9 | 38404500451782 |
10 | 10012323201203 |
11 | 3210225476524 |
12 | 115855694726b |
13 | 57820925235b |
14 | 268855a3d4b1 |
15 | 12569bc56c88 |
hex | 91b2cf7c0b3 |
10012323201203 has 2 divisors, whose sum is σ = 10012323201204. Its totient is φ = 10012323201202.
The previous prime is 10012323201197. The next prime is 10012323201229. The reversal of 10012323201203 is 30210232321001.
It is a weak prime.
It is an emirp because it is prime and its reverse (30210232321001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10012323201203 - 214 = 10012323184819 is a prime.
It is not a weakly prime, because it can be changed into another prime (10012323204203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006161600601 + 5006161600602.
It is an arithmetic number, because the mean of its divisors is an integer number (5006161600602).
Almost surely, 210012323201203 is an apocalyptic number.
10012323201203 is a deficient number, since it is larger than the sum of its proper divisors (1).
10012323201203 is an equidigital number, since it uses as much as digits as its factorization.
10012323201203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 10012323201203 its reverse (30210232321001), we get a palindrome (40222555522204).
The spelling of 10012323201203 in words is "ten trillion, twelve billion, three hundred twenty-three million, two hundred one thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •