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100124133397 is a prime number
BaseRepresentation
bin101110100111111011…
…1010000100000010101
3100120102211012222020221
41131033313100200111
53120023234232042
6113555115354341
710143112043311
oct1351767204025
9316384188227
10100124133397
113950a510392
12174a34529b1
139598452b62
144bbb734b41
1529100a9d67
hex174fdd0815

100124133397 has 2 divisors, whose sum is σ = 100124133398. Its totient is φ = 100124133396.

The previous prime is 100124133371. The next prime is 100124133409. The reversal of 100124133397 is 793331421001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91035561841 + 9088571556 = 301721^2 + 95334^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100124133397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100124133497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50062066698 + 50062066699.

It is an arithmetic number, because the mean of its divisors is an integer number (50062066699).

Almost surely, 2100124133397 is an apocalyptic number.

It is an amenable number.

100124133397 is a deficient number, since it is larger than the sum of its proper divisors (1).

100124133397 is an equidigital number, since it uses as much as digits as its factorization.

100124133397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 34.

Adding to 100124133397 its reverse (793331421001), we get a palindrome (893455554398).

The spelling of 100124133397 in words is "one hundred billion, one hundred twenty-four million, one hundred thirty-three thousand, three hundred ninety-seven".