10012537984147 has 4 divisors (see below), whose sum is σ = 10111672023696. Its totient is φ = 9913403944600.

The previous prime is 10012537984117. The next prime is 10012537984193. The reversal of 10012537984147 is 74148973521001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10012537984147 - 2²³ = 10012529595539 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10012537984094 and 10012537984103.

It is not an unprimeable number, because it can be changed into a prime (10012537984117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49567019623 + ... + 49567019824.

It is an arithmetic number, because the mean of its divisors is an integer number (2527918005924).

Almost surely, 2^{10012537984147} is an apocalyptic number.

10012537984147 is a deficient number, since it is larger than the sum of its proper divisors (99134039549).

10012537984147 is an equidigital number, since it uses as much as digits as its factorization.

10012537984147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99134039548.

The product of its (nonzero) digits is 1693440, while the sum is 52.

The spelling of 10012537984147 in words is "ten trillion, twelve billion, five hundred thirty-seven million, nine hundred eighty-four thousand, one hundred forty-seven".