100130003113133 has 4 divisors (see below), whose sum is σ = 114434289272160. Its totient is φ = 85825716954108.

The previous prime is 100130003113099. The next prime is 100130003113211. The reversal of 100130003113133 is 331311300031001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100130003113133 - 2¹⁴ = 100130003096749 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100130003113433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7152143079503 + ... + 7152143079516.

It is an arithmetic number, because the mean of its divisors is an integer number (28608572318040).

Almost surely, 2^{100130003113133} is an apocalyptic number.

It is an amenable number.

100130003113133 is a deficient number, since it is larger than the sum of its proper divisors (14304286159027).

100130003113133 is an equidigital number, since it uses as much as digits as its factorization.

100130003113133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14304286159026.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 100130003113133 its reverse (331311300031001), we get a palindrome (431441303144134).

The spelling of 100130003113133 in words is "one hundred trillion, one hundred thirty billion, three million, one hundred thirteen thousand, one hundred thirty-three".