Base | Representation |
---|---|
bin | 1001000110110101010101… |
… | …1000011010101100100011 |
3 | 1022110020022021100020002121 |
4 | 2101231111120122230203 |
5 | 2303023111303344024 |
6 | 33143524222325111 |
7 | 2052262335110254 |
oct | 221552530325443 |
9 | 38406267306077 |
10 | 10013001231139 |
11 | 321054317a445 |
12 | 1158705a29797 |
13 | 5782b686b6ba |
14 | 2688bbad8b2b |
15 | 1256db5398e4 |
hex | 91b5561ab23 |
10013001231139 has 2 divisors, whose sum is σ = 10013001231140. Its totient is φ = 10013001231138.
The previous prime is 10013001231119. The next prime is 10013001231161. The reversal of 10013001231139 is 93113210031001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10013001231139 - 219 = 10013000706851 is a prime.
It is a super-2 number, since 2×100130012311392 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10013001231119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006500615569 + 5006500615570.
It is an arithmetic number, because the mean of its divisors is an integer number (5006500615570).
Almost surely, 210013001231139 is an apocalyptic number.
10013001231139 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013001231139 is an equidigital number, since it uses as much as digits as its factorization.
10013001231139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 10013001231139 in words is "ten trillion, thirteen billion, one million, two hundred thirty-one thousand, one hundred thirty-nine".
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