10013001231119 has 2 divisors, whose sum is σ = 10013001231120. Its totient is φ = 10013001231118.

The previous prime is 10013001231049. The next prime is 10013001231139. The reversal of 10013001231119 is 91113210031001.

It is a happy number.

10013001231119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (91113210031001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10013001231119 is a prime.

It is a super-2 number, since 2×10013001231119² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 10013001231094 and 10013001231103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10013001231139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006500615559 + 5006500615560.

It is an arithmetic number, because the mean of its divisors is an integer number (5006500615560).

Almost surely, 2^{10013001231119} is an apocalyptic number.

10013001231119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013001231119 is an equidigital number, since it uses as much as digits as its factorization.

10013001231119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 23.

The spelling of 10013001231119 in words is "ten trillion, thirteen billion, one million, two hundred thirty-one thousand, one hundred nineteen".