100130022314431 has 4 divisors (see below), whose sum is σ = 100130371774632. Its totient is φ = 100129672854232.

The previous prime is 100130022314423. The next prime is 100130022314447. The reversal of 100130022314431 is 134413220031001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100130022314431 - 2³ = 100130022314423 is a prime.

It is a super-2 number, since 2×100130022314431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100130022314396 and 100130022314405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100130022314131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174299956 + ... + 174873481.

It is an arithmetic number, because the mean of its divisors is an integer number (25032592943658).

Almost surely, 2^{100130022314431} is an apocalyptic number.

100130022314431 is a deficient number, since it is larger than the sum of its proper divisors (349460201).

100130022314431 is an equidigital number, since it uses as much as digits as its factorization.

100130022314431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 349460200.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 100130022314431 its reverse (134413220031001), we get a palindrome (234543242345432).

The spelling of 100130022314431 in words is "one hundred trillion, one hundred thirty billion, twenty-two million, three hundred fourteen thousand, four hundred thirty-one".