Base | Representation |
---|---|
bin | 1001000110110101011100… |
… | …1011001010111011010111 |
3 | 1022110020101100221112210201 |
4 | 2101231113023022323113 |
5 | 2303023142004004421 |
6 | 33143531215201331 |
7 | 2052263151566641 |
oct | 221552713127327 |
9 | 38406340845721 |
10 | 10013031313111 |
11 | 3210559156482 |
12 | 1158713b16247 |
13 | 5782bcb71a98 |
14 | 2688c1ac9891 |
15 | 1256ddeccb91 |
hex | 91b572caed7 |
10013031313111 has 2 divisors, whose sum is σ = 10013031313112. Its totient is φ = 10013031313110.
The previous prime is 10013031313039. The next prime is 10013031313123. The reversal of 10013031313111 is 11131313031001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10013031313111 - 243 = 1216938290903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013031313141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006515656555 + 5006515656556.
It is an arithmetic number, because the mean of its divisors is an integer number (5006515656556).
Almost surely, 210013031313111 is an apocalyptic number.
10013031313111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013031313111 is an equidigital number, since it uses as much as digits as its factorization.
10013031313111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 10013031313111 its reverse (11131313031001), we get a palindrome (21144344344112).
The spelling of 10013031313111 in words is "ten trillion, thirteen billion, thirty-one million, three hundred thirteen thousand, one hundred eleven".
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