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100130333257 is a prime number
BaseRepresentation
bin101110101000000111…
…0111010001001001001
3100120110020212221212101
41131100032322021021
53120031331131012
6113555500313401
710143215534563
oct1352016721111
9316406787771
10100130333257
1139512a65439
12174a5542861
139599813b06
144bbc4aa333
1529108d1d57
hex17503ba249

100130333257 has 2 divisors, whose sum is σ = 100130333258. Its totient is φ = 100130333256.

The previous prime is 100130333239. The next prime is 100130333311. The reversal of 100130333257 is 752333031001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99947028736 + 183304521 = 316144^2 + 13539^2 .

It is an emirp because it is prime and its reverse (752333031001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100130333257 - 27 = 100130333129 is a prime.

It is not a weakly prime, because it can be changed into another prime (100130333957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065166628 + 50065166629.

It is an arithmetic number, because the mean of its divisors is an integer number (50065166629).

Almost surely, 2100130333257 is an apocalyptic number.

It is an amenable number.

100130333257 is a deficient number, since it is larger than the sum of its proper divisors (1).

100130333257 is an equidigital number, since it uses as much as digits as its factorization.

100130333257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5670, while the sum is 28.

Adding to 100130333257 its reverse (752333031001), we get a palindrome (852463364258).

The spelling of 100130333257 in words is "one hundred billion, one hundred thirty million, three hundred thirty-three thousand, two hundred fifty-seven".