100131000031 has 2 divisors, whose sum is σ = 100131000032. Its totient is φ = 100131000030.

The previous prime is 100131000019. The next prime is 100131000077. The reversal of 100131000031 is 130000131001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100131000031 - 2⁵ = 100130999999 is a prime.

It is a super-2 number, since 2×100131000031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100130999981 and 100131000017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100131000131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50065500015 + 50065500016.

It is an arithmetic number, because the mean of its divisors is an integer number (50065500016).

Almost surely, 2^100131000031 is an apocalyptic number.

100131000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

100131000031 is an equidigital number, since it uses as much as digits as its factorization.

100131000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 100131000031 its reverse (130000131001), we get a palindrome (230131131032).

It can be divided in two parts, 100 and 131000031, that added together give a palindrome (131000131).

The spelling of 100131000031 in words is "one hundred billion, one hundred thirty-one million, thirty-one", and thus it is an aban number.