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1001311032000 = 26353223187091
BaseRepresentation
bin11101001001000101100…
…10011101001011000000
310112201120002100202021210
432210202302131023000
5112401141111011000
62043555042250120
7132225264224526
oct16444262351300
93481502322253
101001311032000
11356720a78714
12142089056940
1373566a97016
143666c5da316
151b0a68d5350
hexe922c9d2c0

1001311032000 has 224 divisors, whose sum is σ = 3321173366784. Its totient is φ = 265817472000.

The previous prime is 1001311031983. The next prime is 1001311032023. The reversal of 1001311032000 is 2301131001.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5258455 + ... + 5445545.

It is an arithmetic number, because the mean of its divisors is an integer number (14826666816).

Almost surely, 21001311032000 is an apocalyptic number.

1001311032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1001311032000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1660586683392).

1001311032000 is an abundant number, since it is smaller than the sum of its proper divisors (2319862334784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1001311032000 is a wasteful number, since it uses less digits than its factorization.

1001311032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187344 (or 187324 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 1001311032000 its reverse (2301131001), we get a palindrome (1003612163001).

Subtracting from 1001311032000 its reverse (2301131001), we obtain a palindrome (999009900999).

The spelling of 1001311032000 in words is "one trillion, one billion, three hundred eleven million, thirty-two thousand".