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10013114143 = 29370148751
BaseRepresentation
bin10010101001101001…
…11111111100011111
3221211211102220100101
421110310333330133
5131001324123033
64333331441531
7503064031414
oct112464777437
927754386311
1010013114143
11427916194a
121b354562a7
13c3762c616
146adbb810b
153d90ed97d
hex254d3ff1f

10013114143 has 8 divisors (see below), whose sum is σ = 10061827776. Its totient is φ = 9964500000.

The previous prime is 10013114123. The next prime is 10013114161. The reversal of 10013114143 is 34141131001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10013114143 - 29 = 10013113631 is a prime.

It is a super-3 number, since 3×100131141433 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10013114143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013114123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 181018 + ... + 229768.

It is an arithmetic number, because the mean of its divisors is an integer number (1257728472).

Almost surely, 210013114143 is an apocalyptic number.

10013114143 is a deficient number, since it is larger than the sum of its proper divisors (48713633).

10013114143 is an equidigital number, since it uses as much as digits as its factorization.

10013114143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49745.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10013114143 its reverse (34141131001), we get a palindrome (44154245144).

The spelling of 10013114143 in words is "ten billion, thirteen million, one hundred fourteen thousand, one hundred forty-three".

Divisors: 1 293 701 48751 205393 14284043 34174451 10013114143