Base | Representation |
---|---|
bin | 11101001001000101101… |
… | …11011010011000101011 |
3 | 10112201120011210202121021 |
4 | 32210202313122120223 |
5 | 112401141424100212 |
6 | 2043555130153311 |
7 | 132225311245561 |
oct | 16444267323053 |
9 | 3481504722537 |
10 | 1001312331307 |
11 | 356721785922 |
12 | 142089582837 |
13 | 73567130542 |
14 | 3666c857a31 |
15 | 1b0a6a90307 |
hex | e922dda62b |
1001312331307 has 4 divisors (see below), whose sum is σ = 1060213056696. Its totient is φ = 942411605920.
The previous prime is 1001312331293. The next prime is 1001312331329. The reversal of 1001312331307 is 7031332131001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1001312331307 - 27 = 1001312331179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1001312331337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29450362669 + ... + 29450362702.
It is an arithmetic number, because the mean of its divisors is an integer number (265053264174).
Almost surely, 21001312331307 is an apocalyptic number.
1001312331307 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
1001312331307 is a deficient number, since it is larger than the sum of its proper divisors (58900725389).
1001312331307 is an equidigital number, since it uses as much as digits as its factorization.
1001312331307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58900725388.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1001312331307 its reverse (7031332131001), we get a palindrome (8032644462308).
The spelling of 1001312331307 in words is "one trillion, one billion, three hundred twelve million, three hundred thirty-one thousand, three hundred seven".
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