Base | Representation |
---|---|
bin | 1001000110110101110100… |
… | …0111111010011000101111 |
3 | 1022110020122022202101011111 |
4 | 2101231131013322120233 |
5 | 2303023343031402343 |
6 | 33143545142332451 |
7 | 2052265503135415 |
oct | 221553507723057 |
9 | 38406568671144 |
10 | 10013131122223 |
11 | 32105aa527549 |
12 | 115874142a127 |
13 | 578307749728 |
14 | 2688d106b2b5 |
15 | 1256e7b45c9d |
hex | 91b5d1fa62f |
10013131122223 has 2 divisors, whose sum is σ = 10013131122224. Its totient is φ = 10013131122222.
The previous prime is 10013131122199. The next prime is 10013131122289. The reversal of 10013131122223 is 32222113131001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10013131122223 - 25 = 10013131122191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10013131122194 and 10013131122203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10013131123223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006565561111 + 5006565561112.
It is an arithmetic number, because the mean of its divisors is an integer number (5006565561112).
Almost surely, 210013131122223 is an apocalyptic number.
10013131122223 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013131122223 is an equidigital number, since it uses as much as digits as its factorization.
10013131122223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10013131122223 its reverse (32222113131001), we get a palindrome (42235244253224).
The spelling of 10013131122223 in words is "ten trillion, thirteen billion, one hundred thirty-one million, one hundred twenty-two thousand, two hundred twenty-three".
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