10013131320021 has 6 divisors (see below), whose sum is σ = 14463411906710. Its totient is φ = 6675420880008.

The previous prime is 10013131319953. The next prime is 10013131320107. The reversal of 10013131320021 is 12002313131001.

10013131320021 is a `hidden beast` number, since 1 + 0 + 0 + 131 + 313 + 200 + 21 = 666.

10013131320021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 9506060576100 + 507070743921 = 3083190^2 + 712089^2 .

It is not a de Polignac number, because 10013131320021 - 2¹⁰ = 10013131318997 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10013131319976 and 10013131320003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013131300021) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 556285073326 + ... + 556285073343.

Almost surely, 2^{10013131320021} is an apocalyptic number.

It is an amenable number.

10013131320021 is a deficient number, since it is larger than the sum of its proper divisors (4450280586689).

10013131320021 is a wasteful number, since it uses less digits than its factorization.

10013131320021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1112570146675 (or 1112570146672 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 10013131320021 its reverse (12002313131001), we get a palindrome (22015444451022).

The spelling of 10013131320021 in words is "ten trillion, thirteen billion, one hundred thirty-one million, three hundred twenty thousand, twenty-one".