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100131404055025 = 527709871806033
BaseRepresentation
bin10110110001000110101000…
…110001010000000111110001
3111010112110122201020011022111
4112301012220301100013301
5101111023103414230100
6552543422035405321
730043153352161420
oct2661065061200761
9433473581204274
10100131404055025
11299a5543194662
12b292178753841
1343b4473b88b65
141aa25589672b7
15b899aaa296ba
hex5b11a8c501f1

100131404055025 has 24 divisors (see below), whose sum is σ = 141900879976704. Its totient is φ = 68661352300800.

The previous prime is 100131404055017. The next prime is 100131404055239. The reversal of 100131404055025 is 520550404131001.

It is not a de Polignac number, because 100131404055025 - 23 = 100131404055017 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 123824409 + ... + 124630441.

It is an arithmetic number, because the mean of its divisors is an integer number (5912536665696).

Almost surely, 2100131404055025 is an apocalyptic number.

It is an amenable number.

100131404055025 is a deficient number, since it is larger than the sum of its proper divisors (41769475921679).

100131404055025 is an equidigital number, since it uses as much as digits as its factorization.

100131404055025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1515921 (or 1515916 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 100131404055025 its reverse (520550404131001), we get a palindrome (620681808186026).

The spelling of 100131404055025 in words is "one hundred trillion, one hundred thirty-one billion, four hundred four million, fifty-five thousand, twenty-five".

Divisors: 1 5 7 25 35 175 709871 806033 3549355 4030165 4969097 5642231 17746775 20150825 24845485 28211155 124227425 141055775 572179451743 2860897258715 4005256162201 14304486293575 20026280811005 100131404055025