Base | Representation |
---|---|
bin | 10110110001000110101000… |
… | …110001010000000111110001 |
3 | 111010112110122201020011022111 |
4 | 112301012220301100013301 |
5 | 101111023103414230100 |
6 | 552543422035405321 |
7 | 30043153352161420 |
oct | 2661065061200761 |
9 | 433473581204274 |
10 | 100131404055025 |
11 | 299a5543194662 |
12 | b292178753841 |
13 | 43b4473b88b65 |
14 | 1aa25589672b7 |
15 | b899aaa296ba |
hex | 5b11a8c501f1 |
100131404055025 has 24 divisors (see below), whose sum is σ = 141900879976704. Its totient is φ = 68661352300800.
The previous prime is 100131404055017. The next prime is 100131404055239. The reversal of 100131404055025 is 520550404131001.
It is not a de Polignac number, because 100131404055025 - 23 = 100131404055017 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 123824409 + ... + 124630441.
It is an arithmetic number, because the mean of its divisors is an integer number (5912536665696).
Almost surely, 2100131404055025 is an apocalyptic number.
It is an amenable number.
100131404055025 is a deficient number, since it is larger than the sum of its proper divisors (41769475921679).
100131404055025 is an equidigital number, since it uses as much as digits as its factorization.
100131404055025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1515921 (or 1515916 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 100131404055025 its reverse (520550404131001), we get a palindrome (620681808186026).
The spelling of 100131404055025 in words is "one hundred trillion, one hundred thirty-one billion, four hundred four million, fifty-five thousand, twenty-five".
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