10013151133 has 4 divisors (see below), whose sum is σ = 10013421600. Its totient is φ = 10012880668.

The previous prime is 10013151121. The next prime is 10013151151. The reversal of 10013151133 is 33115131001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10013151133 - 2⁵ = 10013151101 is a prime.

It is a super-2 number, since 2×10013151133² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10013151133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013151103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68833 + ... + 157366.

It is an arithmetic number, because the mean of its divisors is an integer number (2503355400).

Almost surely, 2^10013151133 is an apocalyptic number.

It is an amenable number.

10013151133 is a deficient number, since it is larger than the sum of its proper divisors (270467).

10013151133 is an equidigital number, since it uses as much as digits as its factorization.

10013151133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 270466.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 10013151133 its reverse (33115131001), we get a palindrome (43128282134).

The spelling of 10013151133 in words is "ten billion, thirteen million, one hundred fifty-one thousand, one hundred thirty-three".