Base | Representation |
---|---|
bin | 1001000110110110000101… |
… | …1110010110101001101011 |
3 | 1022110020211102002202002122 |
4 | 2101231201132112221223 |
5 | 2303024020223122102 |
6 | 33144000311021455 |
7 | 2052300350432462 |
oct | 221554136265153 |
9 | 38406742082078 |
10 | 10013204114027 |
11 | 3210637751354 |
12 | 115876196a88b |
13 | 5783198c4c4a |
14 | 2688daa2b9d9 |
15 | 1256ee2630a2 |
hex | 91b61796a6b |
10013204114027 has 2 divisors, whose sum is σ = 10013204114028. Its totient is φ = 10013204114026.
The previous prime is 10013204114003. The next prime is 10013204114033. The reversal of 10013204114027 is 72041140231001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10013204114027 - 218 = 10013203851883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10013204113987 and 10013204114005.
It is not a weakly prime, because it can be changed into another prime (10013204114527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006602057013 + 5006602057014.
It is an arithmetic number, because the mean of its divisors is an integer number (5006602057014).
Almost surely, 210013204114027 is an apocalyptic number.
10013204114027 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013204114027 is an equidigital number, since it uses as much as digits as its factorization.
10013204114027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 10013204114027 its reverse (72041140231001), we get a palindrome (82054344345028).
The spelling of 10013204114027 in words is "ten trillion, thirteen billion, two hundred four million, one hundred fourteen thousand, twenty-seven".
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