Base | Representation |
---|---|
bin | 11101001001000110111… |
… | …00010011011001001101 |
3 | 10112201120212000002021222 |
4 | 32210203130103121031 |
5 | 112401201413030442 |
6 | 2044000113333125 |
7 | 132225456404162 |
oct | 16444334233115 |
9 | 3481525002258 |
10 | 1001322001997 |
11 | 356727190629 |
12 | 1420908671a5 |
13 | 73569138245 |
14 | 3666dc54069 |
15 | 1b0a78508d2 |
hex | e92371364d |
1001322001997 has 2 divisors, whose sum is σ = 1001322001998. Its totient is φ = 1001322001996.
The previous prime is 1001322001987. The next prime is 1001322002011. The reversal of 1001322001997 is 7991002231001.
1001322001997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 752150314756 + 249171687241 = 867266^2 + 499171^2 .
It is a cyclic number.
It is not a de Polignac number, because 1001322001997 - 214 = 1001321985613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1001322001907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500661000998 + 500661000999.
It is an arithmetic number, because the mean of its divisors is an integer number (500661000999).
Almost surely, 21001322001997 is an apocalyptic number.
It is an amenable number.
1001322001997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1001322001997 is an equidigital number, since it uses as much as digits as its factorization.
1001322001997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 35.
Adding to 1001322001997 its reverse (7991002231001), we get a palindrome (8992324232998).
The spelling of 1001322001997 in words is "one trillion, one billion, three hundred twenty-two million, one thousand, nine hundred ninety-seven".
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