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10013223113 is a prime number
BaseRepresentation
bin10010101001101010…
…11010100011001001
3221211211122102211022
421110311122203021
5131001341114423
64333334042225
7503064664205
oct112465324311
927754572738
1010013223113
114279226803
121b354a9375
13c3766a0ba
146adc05b05
153d9120dc8
hex254d5a8c9

10013223113 has 2 divisors, whose sum is σ = 10013223114. Its totient is φ = 10013223112.

The previous prime is 10013223019. The next prime is 10013223119. The reversal of 10013223113 is 31132231001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9933710224 + 79512889 = 99668^2 + 8917^2 .

It is a cyclic number.

It is not a de Polignac number, because 10013223113 - 216 = 10013157577 is a prime.

It is a super-2 number, since 2×100132231132 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10013223091 and 10013223100.

It is not a weakly prime, because it can be changed into another prime (10013223119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006611556 + 5006611557.

It is an arithmetic number, because the mean of its divisors is an integer number (5006611557).

Almost surely, 210013223113 is an apocalyptic number.

It is an amenable number.

10013223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10013223113 is an equidigital number, since it uses as much as digits as its factorization.

10013223113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10013223113 its reverse (31132231001), we get a palindrome (41145454114).

The spelling of 10013223113 in words is "ten billion, thirteen million, two hundred twenty-three thousand, one hundred thirteen".