Base | Representation |
---|---|
bin | 101110101000001011… |
… | …0001001101100111111 |
3 | 100120110101110102110011 |
4 | 1131100112021230333 |
5 | 3120032322410444 |
6 | 114000005124051 |
7 | 10143240633352 |
oct | 1352026115477 |
9 | 316411412404 |
10 | 100132231999 |
11 | 39514041a48 |
12 | 174a60b9627 |
13 | 959a02a127 |
14 | 4bbc842299 |
15 | 2910b59734 |
hex | 1750589b3f |
100132231999 has 2 divisors, whose sum is σ = 100132232000. Its totient is φ = 100132231998.
The previous prime is 100132231957. The next prime is 100132232129. The reversal of 100132231999 is 999132231001.
It is a weak prime.
It is an emirp because it is prime and its reverse (999132231001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100132231999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100132231909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066115999 + 50066116000.
It is an arithmetic number, because the mean of its divisors is an integer number (50066116000).
Almost surely, 2100132231999 is an apocalyptic number.
100132231999 is a deficient number, since it is larger than the sum of its proper divisors (1).
100132231999 is an equidigital number, since it uses as much as digits as its factorization.
100132231999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 100132231999 in words is "one hundred billion, one hundred thirty-two million, two hundred thirty-one thousand, nine hundred ninety-nine".
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