Base | Representation |
---|---|
bin | 10010101001101011… |
… | …00010011101001111 |
3 | 221211211201002020221 |
4 | 21110311202131033 |
5 | 131001343134003 |
6 | 4333334452211 |
7 | 503065160506 |
oct | 112465423517 |
9 | 27754632227 |
10 | 10013255503 |
11 | 4279249079 |
12 | 1b35504067 |
13 | c3767ba74 |
14 | 6adc1383d |
15 | 3d912a7bd |
hex | 254d6274f |
10013255503 has 4 divisors (see below), whose sum is σ = 10026414288. Its totient is φ = 10000096720.
The previous prime is 10013255453. The next prime is 10013255509. The reversal of 10013255503 is 30555231001.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30555231001 = 419 ⋅72924179.
It is a cyclic number.
It is not a de Polignac number, because 10013255503 - 213 = 10013247311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10013255509) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6578251 + ... + 6579772.
It is an arithmetic number, because the mean of its divisors is an integer number (2506603572).
Almost surely, 210013255503 is an apocalyptic number.
10013255503 is a deficient number, since it is larger than the sum of its proper divisors (13158785).
10013255503 is an equidigital number, since it uses as much as digits as its factorization.
10013255503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13158784.
The product of its (nonzero) digits is 2250, while the sum is 25.
Adding to 10013255503 its reverse (30555231001), we get a palindrome (40568486504).
The spelling of 10013255503 in words is "ten billion, thirteen million, two hundred fifty-five thousand, five hundred three".
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