Base | Representation |
---|---|
bin | 10010101001101011… |
… | …01101101000100001 |
3 | 221211211210102001102 |
4 | 21110311231220201 |
5 | 131001401120111 |
6 | 4333335444145 |
7 | 503065441124 |
oct | 112465555041 |
9 | 27754712042 |
10 | 10013301281 |
11 | 427927a505 |
12 | 1b35526655 |
13 | c37696859 |
14 | 6adc263bb |
15 | 3d913913b |
hex | 254d6da21 |
10013301281 has 2 divisors, whose sum is σ = 10013301282. Its totient is φ = 10013301280.
The previous prime is 10013301269. The next prime is 10013301293. The reversal of 10013301281 is 18210331001.
It is a balanced prime because it is at equal distance from previous prime (10013301269) and next prime (10013301293).
It can be written as a sum of positive squares in only one way, i.e., 10011003025 + 2298256 = 100055^2 + 1516^2 .
It is a cyclic number.
It is not a de Polignac number, because 10013301281 - 218 = 10013039137 is a prime.
It is a super-2 number, since 2×100133012812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10013301481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5006650640 + 5006650641.
It is an arithmetic number, because the mean of its divisors is an integer number (5006650641).
Almost surely, 210013301281 is an apocalyptic number.
It is an amenable number.
10013301281 is a deficient number, since it is larger than the sum of its proper divisors (1).
10013301281 is an equidigital number, since it uses as much as digits as its factorization.
10013301281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 10013301281 its reverse (18210331001), we get a palindrome (28223632282).
The spelling of 10013301281 in words is "ten billion, thirteen million, three hundred one thousand, two hundred eighty-one".
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