100133110113213 has 4 divisors (see below), whose sum is σ = 133510813484288. Its totient is φ = 66755406742140.

The previous prime is 100133110113203. The next prime is 100133110113307. The reversal of 100133110113213 is 312311011331001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 100133110113213 - 2⁵ = 100133110113181 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100133110113213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100133110113203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16688851685533 + ... + 16688851685538.

It is an arithmetic number, because the mean of its divisors is an integer number (33377703371072).

Almost surely, 2^{100133110113213} is an apocalyptic number.

It is an amenable number.

100133110113213 is a deficient number, since it is larger than the sum of its proper divisors (33377703371075).

100133110113213 is an equidigital number, since it uses as much as digits as its factorization.

100133110113213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33377703371074.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 100133110113213 its reverse (312311011331001), we get a palindrome (412444121444214).

The spelling of 100133110113213 in words is "one hundred trillion, one hundred thirty-three billion, one hundred ten million, one hundred thirteen thousand, two hundred thirteen".