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10013312013 = 315592140969
BaseRepresentation
bin10010101001101011…
…10000010000001101
3221211211210221202220
421110311300100031
5131001401441023
64333340005553
7503065514325
oct112465602015
927754727686
1010013312013
114279287581
121b355308b9
13c3769b6c3
146adc2a285
153d913c3e3
hex254d7040d

10013312013 has 8 divisors (see below), whose sum is σ = 13359652800. Its totient is φ = 6671256288.

The previous prime is 10013311921. The next prime is 10013312033. The reversal of 10013312013 is 31021331001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10013312013 - 221 = 10011214861 is a prime.

It is a super-2 number, since 2×100133120132 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10013311983 and 10013312001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013312033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1065808 + ... + 1075161.

It is an arithmetic number, because the mean of its divisors is an integer number (1669956600).

Almost surely, 210013312013 is an apocalyptic number.

It is an amenable number.

10013312013 is a deficient number, since it is larger than the sum of its proper divisors (3346340787).

10013312013 is a wasteful number, since it uses less digits than its factorization.

10013312013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2142531.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10013312013 its reverse (31021331001), we get a palindrome (41034643014).

The spelling of 10013312013 in words is "ten billion, thirteen million, three hundred twelve thousand, thirteen".

Divisors: 1 3 1559 4677 2140969 6422907 3337770671 10013312013