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100133120221231 is a prime number
BaseRepresentation
bin10110110001001000001111…
…000011111010000000101111
3111010112122002022111102202211
4112301020033003322000233
5101111040112234034411
6552544304223031251
730043244031304426
oct2661101703720057
9433478068442684
10100133120221231
11299a6243999739
12b29257743b527
1343b46885a5816
141aa267c85a2bd
15b89a5b523221
hex5b120f0fa02f

100133120221231 has 2 divisors, whose sum is σ = 100133120221232. Its totient is φ = 100133120221230.

The previous prime is 100133120221213. The next prime is 100133120221241. The reversal of 100133120221231 is 132122021331001.

Together with previous prime (100133120221213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100133120221231 - 211 = 100133120219183 is a prime.

It is a super-2 number, since 2×1001331202212312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100133120221241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50066560110615 + 50066560110616.

It is an arithmetic number, because the mean of its divisors is an integer number (50066560110616).

Almost surely, 2100133120221231 is an apocalyptic number.

100133120221231 is a deficient number, since it is larger than the sum of its proper divisors (1).

100133120221231 is an equidigital number, since it uses as much as digits as its factorization.

100133120221231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 100133120221231 its reverse (132122021331001), we get a palindrome (232255141552232).

The spelling of 100133120221231 in words is "one hundred trillion, one hundred thirty-three billion, one hundred twenty million, two hundred twenty-one thousand, two hundred thirty-one".