Base | Representation |
---|---|
bin | 10110110001001000001111… |
… | …001000000001011010100010 |
3 | 111010112122002101112020202001 |
4 | 112301020033020001122202 |
5 | 101111040113023101010 |
6 | 552544304302114214 |
7 | 30043244043420052 |
oct | 2661101710013242 |
9 | 433478071466661 |
10 | 100133121300130 |
11 | 299a6244566296 |
12 | b29257787b96a |
13 | 43b4688892919 |
14 | 1aa267ca5b562 |
15 | b89a5b687c3a |
hex | 5b120f2016a2 |
100133121300130 has 32 divisors (see below), whose sum is σ = 190842535800576. Its totient is φ = 37697059133184.
The previous prime is 100133121300067. The next prime is 100133121300187. The reversal of 100133121300130 is 31003121331001.
It is a junction number, because it is equal to n+sod(n) for n = 100133121300098 and 100133121300107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71503317 + ... + 72890263.
It is an arithmetic number, because the mean of its divisors is an integer number (5963829243768).
Almost surely, 2100133121300130 is an apocalyptic number.
100133121300130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
100133121300130 is a deficient number, since it is larger than the sum of its proper divisors (90709414500446).
100133121300130 is a wasteful number, since it uses less digits than its factorization.
100133121300130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1811658.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 100133121300130 its reverse (31003121331001), we get a palindrome (131136242631131).
The spelling of 100133121300130 in words is "one hundred trillion, one hundred thirty-three billion, one hundred twenty-one million, three hundred thousand, one hundred thirty".
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