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10013320241 = 41923898139
BaseRepresentation
bin10010101001101011…
…10010010000110001
3221211211211101001122
421110311302100301
5131001402221431
64333340112025
7503065550321
oct112465622061
927754741048
1010013320241
114279292781
121b35535615
13c376a2382
146adc2d281
153d913ea7b
hex254d72431

10013320241 has 4 divisors (see below), whose sum is σ = 10037218800. Its totient is φ = 9989421684.

The previous prime is 10013320217. The next prime is 10013320277. The reversal of 10013320241 is 14202331001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14202331001 = 71200032831.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10013320241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10013320201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11948651 + ... + 11949488.

It is an arithmetic number, because the mean of its divisors is an integer number (2509304700).

Almost surely, 210013320241 is an apocalyptic number.

It is an amenable number.

10013320241 is a deficient number, since it is larger than the sum of its proper divisors (23898559).

10013320241 is an equidigital number, since it uses as much as digits as its factorization.

10013320241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23898558.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10013320241 its reverse (14202331001), we get a palindrome (24215651242).

The spelling of 10013320241 in words is "ten billion, thirteen million, three hundred twenty thousand, two hundred forty-one".

Divisors: 1 419 23898139 10013320241