100135100115341 has 4 divisors (see below), whose sum is σ = 100149439961952. Its totient is φ = 100120760268732.

The previous prime is 100135100115317. The next prime is 100135100115397. The reversal of 100135100115341 is 143511001531001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100135100115341 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100135100115341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100135100115541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7169912831 + ... + 7169926796.

It is an arithmetic number, because the mean of its divisors is an integer number (25037359990488).

Almost surely, 2^{100135100115341} is an apocalyptic number.

It is an amenable number.

100135100115341 is a deficient number, since it is larger than the sum of its proper divisors (14339846611).

100135100115341 is an equidigital number, since it uses as much as digits as its factorization.

100135100115341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14339846610.

The product of its (nonzero) digits is 900, while the sum is 26.

Adding to 100135100115341 its reverse (143511001531001), we get a palindrome (243646101646342).

The spelling of 100135100115341 in words is "one hundred trillion, one hundred thirty-five billion, one hundred million, one hundred fifteen thousand, three hundred forty-one".