Base | Representation |
---|---|
bin | 10110110001001110111011… |
… | …110111001110010001011011 |
3 | 111010120022122200110121202212 |
4 | 112301032323313032101123 |
5 | 101111144330431301021 |
6 | 552551454133345335 |
7 | 30043620225201245 |
oct | 2661167367162133 |
9 | 433508580417685 |
10 | 100140314322011 |
11 | 299a92a5867077 |
12 | b293a4479824b |
13 | 43b5263b7b8a2 |
14 | 1aa2b620a1095 |
15 | b89d2cdcd85b |
hex | 5b13bbdce45b |
100140314322011 has 2 divisors, whose sum is σ = 100140314322012. Its totient is φ = 100140314322010.
The previous prime is 100140314322001. The next prime is 100140314322029. The reversal of 100140314322011 is 110223413041001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100140314322011 - 26 = 100140314321947 is a prime.
It is a super-2 number, since 2×1001403143220112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100140314322001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50070157161005 + 50070157161006.
It is an arithmetic number, because the mean of its divisors is an integer number (50070157161006).
Almost surely, 2100140314322011 is an apocalyptic number.
100140314322011 is a deficient number, since it is larger than the sum of its proper divisors (1).
100140314322011 is an equidigital number, since it uses as much as digits as its factorization.
100140314322011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 100140314322011 its reverse (110223413041001), we get a palindrome (210363727363012).
The spelling of 100140314322011 in words is "one hundred trillion, one hundred forty billion, three hundred fourteen million, three hundred twenty-two thousand, eleven".
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