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10014117 = 33338039
BaseRepresentation
bin100110001100…
…110110100101
3200211202210020
4212030312211
510030422432
6554345353
7151055451
oct46146645
920752706
1010014117
11571a833
12342b259
1320c8119
141489661
15d2c22c
hex98cda5

10014117 has 4 divisors (see below), whose sum is σ = 13352160. Its totient is φ = 6676076.

The previous prime is 10014113. The next prime is 10014163. The reversal of 10014117 is 71141001.

10014117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10014117 - 22 = 10014113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10014096 and 10014105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10014113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1669017 + ... + 1669022.

It is an arithmetic number, because the mean of its divisors is an integer number (3338040).

Almost surely, 210014117 is an apocalyptic number.

It is an amenable number.

10014117 is a deficient number, since it is larger than the sum of its proper divisors (3338043).

10014117 is an equidigital number, since it uses as much as digits as its factorization.

10014117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3338042.

The product of its (nonzero) digits is 28, while the sum is 15.

The square root of 10014117 is about 3164.5089666487. The cubic root of 10014117 is about 215.5448018493.

Adding to 10014117 its reverse (71141001), we get a palindrome (81155118).

The spelling of 10014117 in words is "ten million, fourteen thousand, one hundred seventeen".

Divisors: 1 3 3338039 10014117