Base | Representation |
---|---|
bin | 101110101000011100… |
… | …0111010011000111111 |
3 | 100120111000121101012111 |
4 | 1131100320322120333 |
5 | 3120042141004234 |
6 | 114000532314451 |
7 | 10143411245032 |
oct | 1352070723077 |
9 | 316430541174 |
10 | 100141344319 |
11 | 395191a6195 |
12 | 174a9172a27 |
13 | 959bb9a933 |
14 | 4bbdb35019 |
15 | 2911859664 |
hex | 1750e3a63f |
100141344319 has 2 divisors, whose sum is σ = 100141344320. Its totient is φ = 100141344318.
The previous prime is 100141344313. The next prime is 100141344337. The reversal of 100141344319 is 913443141001.
It is a weak prime.
It is an emirp because it is prime and its reverse (913443141001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100141344319 - 29 = 100141343807 is a prime.
It is a super-2 number, since 2×1001413443192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100141344313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50070672159 + 50070672160.
It is an arithmetic number, because the mean of its divisors is an integer number (50070672160).
Almost surely, 2100141344319 is an apocalyptic number.
100141344319 is a deficient number, since it is larger than the sum of its proper divisors (1).
100141344319 is an equidigital number, since it uses as much as digits as its factorization.
100141344319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 100141344319 in words is "one hundred billion, one hundred forty-one million, three hundred forty-four thousand, three hundred nineteen".
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