10014140113 has 2 divisors, whose sum is σ = 10014140114. Its totient is φ = 10014140112.

The previous prime is 10014140089. The next prime is 10014140231. The reversal of 10014140113 is 31104141001.

10014140113 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8254085904 + 1760054209 = 90852^2 + 41953^2 .

It is a cyclic number.

It is not a de Polignac number, because 10014140113 - 2²⁹ = 9477269201 is a prime.

It is not a weakly prime, because it can be changed into another prime (10018140113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5007070056 + 5007070057.

It is an arithmetic number, because the mean of its divisors is an integer number (5007070057).

Almost surely, 2^10014140113 is an apocalyptic number.

It is an amenable number.

10014140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10014140113 is an equidigital number, since it uses as much as digits as its factorization.

10014140113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10014140113 its reverse (31104141001), we get a palindrome (41118281114).

The spelling of 10014140113 in words is "ten billion, fourteen million, one hundred forty thousand, one hundred thirteen".