Base | Representation |
---|---|
bin | 10110110001010000100000… |
… | …111111101101000100010001 |
3 | 111010120111000221011000221012 |
4 | 112301100200333231010101 |
5 | 101111211314311402423 |
6 | 552552334344140305 |
7 | 30044010250122023 |
oct | 2661204077550421 |
9 | 433514027130835 |
10 | 100142011044113 |
11 | 299a9a965a0545 |
12 | b294238a67695 |
13 | 43b547454b16c |
14 | 1aa2c83572013 |
15 | b89dcbd36078 |
hex | 5b1420fed111 |
100142011044113 has 8 divisors (see below), whose sum is σ = 100316639687040. Its totient is φ = 99967396106320.
The previous prime is 100142011044109. The next prime is 100142011044137. The reversal of 100142011044113 is 311440110241001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100142011044113 - 22 = 100142011044109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (100142011044613) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11255048 + ... + 18082038.
It is an arithmetic number, because the mean of its divisors is an integer number (12539579960880).
Almost surely, 2100142011044113 is an apocalyptic number.
It is an amenable number.
100142011044113 is a deficient number, since it is larger than the sum of its proper divisors (174628642927).
100142011044113 is an equidigital number, since it uses as much as digits as its factorization.
100142011044113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6852567.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 100142011044113 its reverse (311440110241001), we get a palindrome (411582121285114).
The spelling of 100142011044113 in words is "one hundred trillion, one hundred forty-two billion, eleven million, forty-four thousand, one hundred thirteen".
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