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100144013003 = 1069564116607
BaseRepresentation
bin101110101000100001…
…1000101111011001011
3100120111012121221221122
41131101003011323023
53120043331404003
6114001105425455
710143443031326
oct1352103057313
9316435557848
10100144013003
113951a759211
12174aa03b28b
13959c5c3538
144bc022b7bd
152911bd5238
hex17510c5ecb

100144013003 has 8 divisors (see below), whose sum is σ = 100261499520. Its totient is φ = 100026573120.

The previous prime is 100144012973. The next prime is 100144013063. The reversal of 100144013003 is 300310441001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100144013003 - 218 = 100143750859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100144013063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6021926 + ... + 6038532.

It is an arithmetic number, because the mean of its divisors is an integer number (12532687440).

Almost surely, 2100144013003 is an apocalyptic number.

100144013003 is a deficient number, since it is larger than the sum of its proper divisors (117486517).

100144013003 is a wasteful number, since it uses less digits than its factorization.

100144013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23317.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 100144013003 its reverse (300310441001), we get a palindrome (400454454004).

The spelling of 100144013003 in words is "one hundred billion, one hundred forty-four million, thirteen thousand, three".

Divisors: 1 1069 5641 16607 6030229 17752883 93680087 100144013003