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100145050543 = 891125225287
BaseRepresentation
bin101110101000100011…
…1000011001110101111
3100120111021120200012001
41131101013003032233
53120044113104133
6114001143553131
710143454612246
oct1352107031657
9316437520161
10100145050543
11395202a778a
12174aa45b7a7
13959c897875
144bc041b95d
152911d3c87d
hex17511c33af

100145050543 has 4 divisors (see below), whose sum is σ = 101270275920. Its totient is φ = 99019825168.

The previous prime is 100145050541. The next prime is 100145050547. The reversal of 100145050543 is 345050541001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100145050543 - 21 = 100145050541 is a prime.

It is a super-2 number, since 2×1001450505432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100145050541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562612555 + ... + 562612732.

It is an arithmetic number, because the mean of its divisors is an integer number (25317568980).

Almost surely, 2100145050543 is an apocalyptic number.

100145050543 is a deficient number, since it is larger than the sum of its proper divisors (1125225377).

100145050543 is an equidigital number, since it uses as much as digits as its factorization.

100145050543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1125225376.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 100145050543 its reverse (345050541001), we get a palindrome (445195591544).

The spelling of 100145050543 in words is "one hundred billion, one hundred forty-five million, fifty thousand, five hundred forty-three".

Divisors: 1 89 1125225287 100145050543