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10020000102251 is a prime number
BaseRepresentation
bin1001000111001111011010…
…0010111111011101101011
31022110220101000221201100012
42101303312202333131223
52303131430011233001
633151042520402135
72052630641405306
oct221636642773553
938426330851305
1010020000102251
113213504922947
121159b3991634b
13578b6086a859
14268d8343db3d
1512599abce2bb
hex91cf68bf76b

10020000102251 has 2 divisors, whose sum is σ = 10020000102252. Its totient is φ = 10020000102250.

The previous prime is 10020000102191. The next prime is 10020000102253. The reversal of 10020000102251 is 15220100002001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10020000102251 is a prime.

It is a super-2 number, since 2×100200001022512 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10020000102253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10020000102253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010000051125 + 5010000051126.

It is an arithmetic number, because the mean of its divisors is an integer number (5010000051126).

Almost surely, 210020000102251 is an apocalyptic number.

10020000102251 is a deficient number, since it is larger than the sum of its proper divisors (1).

10020000102251 is an equidigital number, since it uses as much as digits as its factorization.

10020000102251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 14.

Adding to 10020000102251 its reverse (15220100002001), we get a palindrome (25240100104252).

The spelling of 10020000102251 in words is "ten trillion, twenty billion, one hundred two thousand, two hundred fifty-one".