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100200212113 = 436833341027
BaseRepresentation
bin101110101010001100…
…1011110011010010001
3100120122010101011122011
41131110121132122101
53120202223241423
6114010434142521
710145024515201
oct1352431363221
9316563334564
10100200212113
1139549453461
1217504a21a41
1395ab13c451
144bc789a401
152916ad6b0d
hex175465e691

100200212113 has 8 divisors (see below), whose sum is σ = 102545755488. Its totient is φ = 97855364544.

The previous prime is 100200212053. The next prime is 100200212137. The reversal of 100200212113 is 311212002001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100200212113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100200212093 and 100200212102.

It is not an unprimeable number, because it can be changed into a prime (100200212143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123306 + ... + 464332.

It is an arithmetic number, because the mean of its divisors is an integer number (12818219436).

Almost surely, 2100200212113 is an apocalyptic number.

It is an amenable number.

100200212113 is a deficient number, since it is larger than the sum of its proper divisors (2345543375).

100200212113 is an equidigital number, since it uses as much as digits as its factorization.

100200212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 347903.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100200212113 its reverse (311212002001), we get a palindrome (411412214114).

The spelling of 100200212113 in words is "one hundred billion, two hundred million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 43 6833 293819 341027 14664161 2330237491 100200212113