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1002011122117 is a prime number
BaseRepresentation
bin11101001010011001000…
…01000101100111000101
310112210100212201000101101
432211030201011213011
5112404104321401432
62044152331500101
7132251525002555
oct16451441054705
93483325630341
101002011122117
11356a50179795
121422435b7631
1373648b38425
14366d7599165
151b0e80c44e7
hexe94c8459c5

1002011122117 has 2 divisors, whose sum is σ = 1002011122118. Its totient is φ = 1002011122116.

The previous prime is 1002011122109. The next prime is 1002011122141. The reversal of 1002011122117 is 7112211102001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 529868982241 + 472142139876 = 727921^2 + 687126^2 .

It is an emirp because it is prime and its reverse (7112211102001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1002011122117 - 23 = 1002011122109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1002011122094 and 1002011122103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1002011122157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501005561058 + 501005561059.

It is an arithmetic number, because the mean of its divisors is an integer number (501005561059).

Almost surely, 21002011122117 is an apocalyptic number.

It is an amenable number.

1002011122117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002011122117 is an equidigital number, since it uses as much as digits as its factorization.

1002011122117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1002011122117 its reverse (7112211102001), we get a palindrome (8114222224118).

The spelling of 1002011122117 in words is "one trillion, two billion, eleven million, one hundred twenty-two thousand, one hundred seventeen".