Base | Representation |
---|---|
bin | 101110101010001110… |
… | …1010000001010010011 |
3 | 100120122012020110221121 |
4 | 1131110131100022103 |
5 | 3120203001433243 |
6 | 114010511303111 |
7 | 10145036111125 |
oct | 1352435201223 |
9 | 316565213847 |
10 | 100201202323 |
11 | 39549a6a412 |
12 | 1750521aa97 |
13 | 95ab3c8081 |
14 | 4bc7a77215 |
15 | 2916c301ed |
hex | 1754750293 |
100201202323 has 2 divisors, whose sum is σ = 100201202324. Its totient is φ = 100201202322.
The previous prime is 100201202281. The next prime is 100201202327. The reversal of 100201202323 is 323202102001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100201202323 - 229 = 99664331411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100201202297 and 100201202306.
It is not a weakly prime, because it can be changed into another prime (100201202327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50100601161 + 50100601162.
It is an arithmetic number, because the mean of its divisors is an integer number (50100601162).
Almost surely, 2100201202323 is an apocalyptic number.
100201202323 is a deficient number, since it is larger than the sum of its proper divisors (1).
100201202323 is an equidigital number, since it uses as much as digits as its factorization.
100201202323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 100201202323 its reverse (323202102001), we get a palindrome (423403304324).
The spelling of 100201202323 in words is "one hundred billion, two hundred one million, two hundred two thousand, three hundred twenty-three".
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