Base | Representation |
---|---|
bin | 11101001010011001001… |
… | …01001101010000010011 |
3 | 10112210100221201212201011 |
4 | 32211030211031100103 |
5 | 112404110110431003 |
6 | 2044152410551351 |
7 | 132251540121121 |
oct | 16451445152023 |
9 | 3483327655634 |
10 | 1002012202003 |
11 | 356a5084705a |
12 | 142243a38557 |
13 | 73649125b07 |
14 | 366d779a911 |
15 | 1b0e823946d |
hex | e94c94d413 |
1002012202003 has 2 divisors, whose sum is σ = 1002012202004. Its totient is φ = 1002012202002.
The previous prime is 1002012201977. The next prime is 1002012202019. The reversal of 1002012202003 is 3002022102001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002012202003 - 229 = 1001475331091 is a prime.
It is not a weakly prime, because it can be changed into another prime (1002012200003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501006101001 + 501006101002.
It is an arithmetic number, because the mean of its divisors is an integer number (501006101002).
Almost surely, 21002012202003 is an apocalyptic number.
1002012202003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002012202003 is an equidigital number, since it uses as much as digits as its factorization.
1002012202003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 1002012202003 its reverse (3002022102001), we get a palindrome (4004034304004).
The spelling of 1002012202003 in words is "one trillion, two billion, twelve million, two hundred two thousand, three".
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