Base | Representation |
---|---|
bin | 11101001010011001001… |
… | …01001101100001100111 |
3 | 10112210100221201221020012 |
4 | 32211030211031201213 |
5 | 112404110110444421 |
6 | 2044152411000435 |
7 | 132251540124263 |
oct | 16451445154147 |
9 | 3483327657205 |
10 | 1002012203111 |
11 | 356a50847977 |
12 | 142243a3911b |
13 | 7364912647a |
14 | 366d779b0a3 |
15 | 1b0e823995b |
hex | e94c94d867 |
1002012203111 has 2 divisors, whose sum is σ = 1002012203112. Its totient is φ = 1002012203110.
The previous prime is 1002012203051. The next prime is 1002012203147. The reversal of 1002012203111 is 1113022102001.
1002012203111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002012203111 - 226 = 1001945094247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002012203611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501006101555 + 501006101556.
It is an arithmetic number, because the mean of its divisors is an integer number (501006101556).
Almost surely, 21002012203111 is an apocalyptic number.
1002012203111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002012203111 is an equidigital number, since it uses as much as digits as its factorization.
1002012203111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1002012203111 its reverse (1113022102001), we get a palindrome (2115034305112).
The spelling of 1002012203111 in words is "one trillion, two billion, twelve million, two hundred three thousand, one hundred eleven".
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