10020144331231 has 8 divisors (see below), whose sum is σ = 10123507945040. Its totient is φ = 9916782006528.

The previous prime is 10020144331213. The next prime is 10020144331237. The reversal of 10020144331231 is 13213344102001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10020144331231 - 2⁵ = 10020144331199 is a prime.

It is a super-2 number, since 2×10020144331231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10020144331196 and 10020144331205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10020144331237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28849480 + ... + 29194738.

It is an arithmetic number, because the mean of its divisors is an integer number (1265438493130).

Almost surely, 2^{10020144331231} is an apocalyptic number.

10020144331231 is a deficient number, since it is larger than the sum of its proper divisors (103363613809).

10020144331231 is an equidigital number, since it uses as much as digits as its factorization.

10020144331231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 644553.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 10020144331231 its reverse (13213344102001), we get a palindrome (23233488433232).

The spelling of 10020144331231 in words is "ten trillion, twenty billion, one hundred forty-four million, three hundred thirty-one thousand, two hundred thirty-one".