1002015344131 has 2 divisors, whose sum is σ = 1002015344132. Its totient is φ = 1002015344130.

The previous prime is 1002015344093. The next prime is 1002015344147. The reversal of 1002015344131 is 1314435102001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1002015344131 - 2³³ = 993425409539 is a prime.

It is a super-3 number, since 3×1002015344131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1002015344096 and 1002015344105.

It is not a weakly prime, because it can be changed into another prime (1002015344171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501007672065 + 501007672066.

It is an arithmetic number, because the mean of its divisors is an integer number (501007672066).

Almost surely, 2^{1002015344131} is an apocalyptic number.

1002015344131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002015344131 is an equidigital number, since it uses as much as digits as its factorization.

1002015344131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

The spelling of 1002015344131 in words is "one trillion, two billion, fifteen million, three hundred forty-four thousand, one hundred thirty-one".