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100202100019933 is a prime number
BaseRepresentation
bin10110110010001000011110…
…100100111101001011011101
3111010210020010122011021120011
4112302020132210331023131
5101113202400101114213
6553040113111323221
730051235310025322
oct2662103644751335
9433706118137504
10100202100019933
1129a2252121a43a
12b2a3a08680511
1343bb02c55c062
141aa5b43b86b49
15b8b7472b203d
hex5b221e93d2dd

100202100019933 has 2 divisors, whose sum is σ = 100202100019934. Its totient is φ = 100202100019932.

The previous prime is 100202100019919. The next prime is 100202100020017. The reversal of 100202100019933 is 339910001202001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99938369498724 + 263730521209 = 9996918^2 + 513547^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100202100019933 is a prime.

It is a super-4 number, since 4×1002021000199334 (a number of 57 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100202100019895 and 100202100019904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100202190019933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50101050009966 + 50101050009967.

It is an arithmetic number, because the mean of its divisors is an integer number (50101050009967).

Almost surely, 2100202100019933 is an apocalyptic number.

It is an amenable number.

100202100019933 is a deficient number, since it is larger than the sum of its proper divisors (1).

100202100019933 is an equidigital number, since it uses as much as digits as its factorization.

100202100019933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916, while the sum is 31.

The spelling of 100202100019933 in words is "one hundred trillion, two hundred two billion, one hundred million, nineteen thousand, nine hundred thirty-three".