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1002091210033 is a prime number
BaseRepresentation
bin11101001010100010100…
…10100110010100110001
310112210120110101220100111
432211101102212110301
5112404240322210113
62044204312221321
7132253516513204
oct16452122462461
93483513356314
101002091210033
11356a913aaa51
1214226639a841
137365c5c9824
143670408593b
151b10014413d
hexe9514a6531

1002091210033 has 2 divisors, whose sum is σ = 1002091210034. Its totient is φ = 1002091210032.

The previous prime is 1002091209997. The next prime is 1002091210037. The reversal of 1002091210033 is 3300121902001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 787377599649 + 214713610384 = 887343^2 + 463372^2 .

It is an emirp because it is prime and its reverse (3300121902001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1002091210033 - 221 = 1002089112881 is a prime.

It is a super-2 number, since 2×10020912100332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1002091209986 and 1002091210013.

It is not a weakly prime, because it can be changed into another prime (1002091210037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501045605016 + 501045605017.

It is an arithmetic number, because the mean of its divisors is an integer number (501045605017).

Almost surely, 21002091210033 is an apocalyptic number.

It is an amenable number.

1002091210033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002091210033 is an equidigital number, since it uses as much as digits as its factorization.

1002091210033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

The spelling of 1002091210033 in words is "one trillion, two billion, ninety-one million, two hundred ten thousand, thirty-three".