Base | Representation |
---|---|
bin | 101110101010100011… |
… | …0110111001010101101 |
3 | 100120122221202122110112 |
4 | 1131111012313022231 |
5 | 3120213300004442 |
6 | 114011541145405 |
7 | 10145230610666 |
oct | 1352506671255 |
9 | 316587678415 |
10 | 100212109997 |
11 | 3955513a51a |
12 | 175089bb265 |
13 | 95b0746b0c |
14 | 4bc92b636d |
15 | 2917b87082 |
hex | 17551b72ad |
100212109997 has 2 divisors, whose sum is σ = 100212109998. Its totient is φ = 100212109996.
The previous prime is 100212109993. The next prime is 100212110027. The reversal of 100212109997 is 799901212001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50275056841 + 49937053156 = 224221^2 + 223466^2 .
It is an emirp because it is prime and its reverse (799901212001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100212109997 - 22 = 100212109993 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100212109993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106054998 + 50106054999.
It is an arithmetic number, because the mean of its divisors is an integer number (50106054999).
Almost surely, 2100212109997 is an apocalyptic number.
It is an amenable number.
100212109997 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212109997 is an equidigital number, since it uses as much as digits as its factorization.
100212109997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20412, while the sum is 41.
The spelling of 100212109997 in words is "one hundred billion, two hundred twelve million, one hundred nine thousand, nine hundred ninety-seven".
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